Dock 3 0 9 Meters

  1. 3 Divided By 0 Equals
  2. Dock 3 0 9 Meters =
  3. Dock 3 0 9 Meters Equals

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Practice 6D: 1 2 3 4 Go up
Momentum and Impulse - by Stephanie Culnane, 2001

1.A 63.0 kg astronaut is on a spacewalk when the tether line to the shuttle breaks.The astronaut is able to throw a 10.0 kg oxygen tank in a direction away from the shuttle with a speed of 12 m/s, propelling the astronaut back to the shuttle.Assuming that the astronaut starts from rest, find the final speed of the astronaut after throwing the tank.

Here's what you know, astronaut's m = 63.0 kg, tanks = 10.0 kg, tank's v = 12.0 m/s. Use the formula mv = mv. Plug in (10.0 kg)

(12 m/s) = (63.0 kg)(v). astronaut's v = 1.9 m/s.


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2. An 85.0 kg fisherman jumps from a dock into a 135.0 kg rowboat at rest on the west side of the dock. If the velocity of the fisherman is 4.30 m/s to the west as he leaves the dock, what is the final velocity of the fisherman and the boat?

Here's what you know, fisherman's m = 85.0 kg, boat's m = 135.0 kg, fisherman's v = 4.30 m/s.Use the formula mv = mv.Plug in (85.0 kg)(4.30 m/s) = (85.0 kg + 135.0 kg)(v).v = 1.66 m/s.

3. Each croquet ball in a set has mass of 0.50 kg.The green ball, traveling at 12.0 m/s, strikes the blue ball, which is at rest.Assuming that the balls slide on a frictionless surface and all collisions are head-on, fine the final speed of the blue ball in each of the following situations:

a.The green ball stops moving after it strikes the blue ball.

3 Divided By 0 Equals

b.The green ball continues moving after the collision at 2.4 m/s in the same direction.

c.The green ball continues moving after the collision at 0.3 m/s in the same direction.

Here's what you know m = 0.50 kg, green ball's v = 12.0 m/s.

a.Use the formula mv = mv.Plug in (0.50 kg)(12.0 m/s) = (0.50 kg)(v).v = 12.0 m/s.

b.Use the formula mv = mv + mv.Plug in (0.50 kg)(12.0 m/s) = (0.50 kg)(2.4 m/v) + (0.50 kg)(v).v = 9.6 m/s.

c.Use the formula mv = mv + mv.Plug in (0.50 kg)(12.0 m/s) = (0.50 kg)(0.3 m/s) + (0.50 kg)(v).v = 11.7 m/s

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Dock 3 0 9 Meters =

Dock 3 0 9 meters equals

4. A boy on a 2.0 kg skateboard initially at rest tosses an 8.0 kg jug of water in the forward direction.If the jug has a speed of 3.0 m/s relative to the ground and the boy and skateboard move in the opposite direction at 0.60 m/s, find the boy's mass.

The total momentum before and after is zero, so if the jug of water has a momentum of (p = mv) (8.0 kg)(3.0 m/s) = 24 kgm/s forward, which means the skateboard and boy must have gained an equal but opposite momentum backward.
So if p = mv, and p = 24 kgm/s backwards, and v = .60 m/s:
24 kgm/s = m(.60 m/s)
then the boy and his board must have a total mass of 40 kg, which means the boy has a mass of 38 kg, if the board has a mass of 2 kg.

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Dock 3 0 9 Meters Equals

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